-=> Quoting Keith Fowler to Paul Edwards <=-

Hello Keith,

KF> While I'm here though, could you please tell me why this doesn't
KF> work porperly:

KF> char name[30];
KF> printf("Please Enter Name: ");
KF> scanf("%s",name);

KF> when this inputs the string, if I have a space in bewteen
KF> something (for example "Keith Fowler") it only puts
"Keith" in
KF> the name[30], then if I do another scanf it then puts "Fowler"
KF> starigh into that string....

Sorry, that's the way scanf() works - it uses white space as a
separator.  It's a tricky function to use & it can even be
dangerous.  For example, with your code above, if the user puts in a
string which is longer than 29 characters, it will overrun your
name[] array.  This may not actually hurt in some circumstances, but
in others it will cause a crash.

KF> Am I using a wrong command??, or am I using this one wrong?

Both.  :) Most programmers avoid scanf() like the plague, mainly
because of the problem I mentioned above.

Try this:

/*
 *  Fgets demo. Public domain.
 *  Tested Aug 25 1996 23:54:04
 */

#include 

#define NAMEMAX 30

int main(void)
{
    char name[NAMEMAX];

    do
    {
        printf("Please Enter Name: ");
        fgets(name, NAMEMAX, stdin);
        printf("Name = %s\n", name);
    } while (*name != '\n');

    return 0;
}

/* * * * * * * * * * * * * * * * * * * * */

In more complex cases, you can use sscanf() to parse the data one
you've read it into a large enough array.

I hope this helps,

Michael Stapleton of Graphic Bits.

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