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| subject: | Take out dups in a list |
(Continued from previous message...)
JB> NH> second_list[counter2] = first_list[counter1];
JB> NH> counter1++;
JB> NH> counter2++;
JB> NH> } else {
JB> NH> counter1++;
JB> NH> }
JB> NH> }
JB> NH> }
JB>the only problem I see is there's no anouncement of the number of
JB>unique valies found in the list...
You must order your beer with egg in it.
JB>immangine the first array had {-1;-1;0;0} in it.
JB>the second array gets {-1;0;0;0;}
JB>(becaue you initialise it to all 0 in main)
JB>but it's not immediately obvious wither the second element is a
JB>number form the first list or marks the end...
True. In thinking about that problem the only way (that I can see) to
overcome it would be to dynamically create an array based on the size of
the input data set OR do a linked list thing.
þ CMPQwk 1.42 999
--- Maximus/2 3.01
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