-=> Quoting John Allen to Cameron Hall <=-
 JA> I am far, far, far from being knowledgable about ANYTHING
 JA> digital, but  in thinking your reply through, it would seem that the
 JA> rotation speed is the  same for the inside edge of the CD as it is for
 JA> the outside edge. When point A  of the disk interior edge passes a
Take one of your own disks to any store that sells either portables or
units that have a window so you can see the disk while playing.  Play
the first track, then go to the last.  You'll see what I mean. :-)
 JA> stationary point off the disk 500 times in  a minute, so would point B
 JA> on the exterior edge.  My laymans logic would think the
 JA> difference is the amount of digital  data read from the inside track
 JA> versus the outside track would be very  different, with the exterior
 JA> providing more data than the interior, provided  it was given data at
 JA> the same density (wrong term?).  Where am I missing the boat?
The datastream from the CD must be constant.  The CD employs what's
known as CLV, constant linear velocity.  If you remember back to your
vinyl days, :-) the inner groves of a record always had more distortion.
This was due to both the Geometry of the tone arm but also due to the
fact that more vinyl passed by the sylus at the outer edge than in the
centre.  The CD compansates for that by spinning the disk faster at the
inner diameters, and since the CD is read from centre to edge, it spins
the fastest at the start.
See ya, Cameron Hall
cameron.hall@bluebeam.gryn.org | ad121@freenet.hamilton.on.ca
Blue Beam BBS | 905 662 5784 | Stoney Creek Ontario Canada | v34 vFC FAX
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