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echo: atm
to: ATM
from: jlerch1{at}tampabay.rr.com
date: 2003-05-15 13:28:14
subject: Re: ATM Robo Misalignment Calculations, did I do this right?

From: "James Lerch" 
To: "Jeff Anderson-Lee" ,
"ATM List"
        
Cc: 
Reply-To: "James Lerch" 


----- Original Message -----
From: "Jeff Anderson-Lee" 

> > Couder/Video = Still using the Couder mask, however replaced the eyeball
> > with a video camera and Television monitor.  Note, this was just a
single
> > impromptu run.
>
> It would be interesting to formalize this and capture several images at
each
> point where the human decided the grays were equal and see what the
computer
> analysis of those positions was.
>

Hi Jeff,

When the optic returns from testing (and depending on the results!) Yes, I
agree this would be interesting!

> How do these dimensions relate to the apparent pixel width of the
apparatus?

Each pixel represents about 0.04" of an inch of surface area, In each
frame of video data I grab a vertical line of 11 pixels (I've played with
the arrangement of pixels, nothing I did seemed to make a measurable change
in results).  Anyways, with my single row of 11 pixels, in effect each zone
radius is the average intensity of a 0.04" wide x 0.44" tall
strip of pixels.

As far as positional accuracy (finding the mirror center in software, and
calculating the correct zone radius) the software is usually within a few
pixels.  I should be pretty close as far as measuring the correct zone
radius location.

I did one experiment, where I assumed a perfect surface (parabolic) and
using my knife edge readings, I then 'solved' for the zone radiuses (using
the outer zone as the common point).  The result of this little experiment
showed I would have had to mis-located zone 1 more than an inch in radius!


Take Care,
James Lerch
http://lerch.no-ip.com/atm (My telescope construction,testing, and coating site)

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