Hello James,

JM> >> If you declare a pointer to a char or structure:

JM> >> char *cp[];

JM> >> Since I am declaring a POINTER, must I declare a size NOW
JM> >> between the square brackets or will this be catered for when
JM> >> I MALLOC?

DN> > This declaration is for an array of pointers, not 'a pointer'.
DN> > Yes, it requires a size (how many pointers go into the array) if
DN> > it is the definition and not simply a declaration.

 The definition creates the space for the pointer array, then you
call malloc() or copy existing string addresses to initialize these
pointers.

JM> Okay that makes sense. But what if it was:

JM> (char *)cp[];

JM> In other words, if I have the syntax right, a pointer to an array of
JM> characters.Would I need a number in the square brackets?

 You can include the array size, if you want to. The syntax is

 char (*cp)[STRINGSIZE];

 However, such an object is virtually equivalent to

 char **cp;

 Hope this helps,

Michael Stapleton of Graphic Bits.

___I'm only here for the taglines.

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