-> The terminal velocity should be reached when the drag force equals
-> the gravitational force.  In terms of an equation, it is as follows:
-> 0.5 * d * C * A * v^2 = m * g
->
-> where d is the density of air, C is the drag coefficient, A is the
-> cross-sectional area, v is velocity, m is mass, and g is the
-> gravitational constant (32 ft/sec^2).  The left side of the equation
-> is the drag force, while the right side is the gravitational force.
-> Solving for the velocity yields the following equation:
->
-> v = sqrt( (2 * m * g / d * C * A) )
->
-> Of course you must use the correct units in the equation, and the
-> drag coefficient C must be found experimentally.
Because * and / take equal precedent, I think you meant:
v = sqrt(  (2 * m * g) / ( d * C * A) )
The only question that remains is whether the drag coefficient C as used
in your formula is the same "Ballistic Coefficient" as used by the
bullet makers to describe their bullets.  BC is something that can be
looked up in manufacturer's tables.
Only problem is that BC changes with velocity.  In other words,
the BC of a bullet at 1000 fps is not usually the same as when
the same bullet is travelling at 2000 fps.
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