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| subject: | OOP |
CM> (C + OOP == C++) // originally had (C++ == C + OOP) CM> // wouldn't be right... would it? Neither is right; the result of the comparison is unspecified because we don't know which side of the comparison operator is evaluated first - in principle both may be evaluated at the same time. Thomas --- þ MM 1.0 #0113 þ Nostalgia isn't what it used to be. ---------------* Origin: McMeier & Son BBS (2:301/138) |
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