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| subject: | Re: ATM How much dental plaster? |
From: "Bill T."
To: atm{at}shore.net
Cc: rflrs{at}rcn.com
Reply-To: "Bill T."
>Using lbs/in^3:
>
>Assuming that whatever water in it goes away with drying, that would
>make a cubic foot of it weigh 1728*0.05 lbs or about 86 lbs. If
>water is 62 lbs per cubic foot, that would make the specific gravity
>of it about 1.39. This seems suspiciously low to me. Am I missing
>something here?
The units are "lbs. of dry plaster," and "inches of tool
thickness."
I plead empiricism. The formula has often been observed to produce tools
near the desired thickness. Strange are the ways of plaster chemistry -
about 1/2 of the water stays behind. One test for tool dryness is to plot
the reduction in weight over time, until the curve flattens out.
Simplified formula:
pounds_of_dry_hyrdrostone = inches_of_tool_thickness * diameter *
diameter * 0.04
First time around, try a factor of 0.05, then for subsequent use scale the
factor by the ratio of:
thickness_you_wanted / thickness_you_got
Bill T.
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