Good ${greeting_time}, Maurice!

15 Jan 2015 05:27:16, you wrote to Nicholas Boel:

 MK> With a basic knowledge of how utf-8 works.  For all 2 byte
 MK> characters, the leading byte is restricted from 0xc2 to 0xdf

30 different values.

 MK> and all trailing bytes from 0x80 to 0xbf in one-byte-speak.

64 different values. The total number of characters is 30*64 == 1920

 MK> Note that between leading and trailing bytes there is no crossover,
 MK> and by doing simple math, that means that all utf-8 characters can
 MK> be remapped to a total of 92 7-bit codes.

7 bits will give you only 128 characters, but you need 1920.
They will fit in 11 bits, but that will still require 2 bytes.


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Alexey V. Vissarionov aka Gremlin from Kremlin
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