Hi,

KH>> I was accessing varibles of the seperate argv's by using *(*
PE>and  KH>> found that if I did a plain argv++ it would only goto the nex
PE>character  KH>> in argv, not the next array element...

If you had "(*argv)++" it would explain that.

[stuff deleted]

KH>         *(argv++); /* if I replace this with argv++ it doesn't work
KH>                    /* btw, this it the line it gives the warning on

The deference doesn't do anything in this case - it *should* be exactly the 
same as putting "argv++".  

[more stuff deleted]

Try this:

/* ------------------ */
#include 
#include 

int main (int argc, char *argv[])
{
    int i;

    /* This... */
    for (i = 0; i < argc; ++i)
        puts (argv[i]);

    /* ... does the same as this. */
    while (argc--)
        puts (*argv++);
    
    return EXIT_SUCCESS;
}
/* ------------------ */

The above should work.  Argv[0] is the name of the program you are 
executing - I think this is guaranteed in the Ansi standard.

Hope this helps!  Got any other problems I can help with?

Glen C.

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 * WR 1.31 [NR] * UNREGISTERED EVALUATION COPY


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