dn>     foo(T_long, 983985L, T_ptr, (void*)NULL, T_end);

dn> (note the cast on NULL is just a precaution and not necessary - except, of 
dn> course, for portability - if either your compiler #define's NULL to be 
dn> (void*)0, or #define'd as 0 and sizeof(int)==sizeof(void*)).

I thought NULL was guaranteed to be a valid pointer, no need for
the (void *) typecast?  It's only 0 that needs a typecast.  
BFN.  Paul.
@EOT:

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