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| subject: | Re: math question |
G'morning again David...
DW> I have developed a strong suspicion that, if the circles
DW> overlap sufficiently to reduce the total area from 60 to 36
DW> cm^2, then the area covered by all three will always be *more
DW> than* 3 cm^2. However, I have not yet been able to prove this
DW> in the general case.
DW> Any ideas about this?
Accepting the 20cm^2 circles must cover 36cms^2 only gets you....
Cover Segment Cm^2 Total Cm^2
Thrice 1.1572999 1.1572999
Twice 7.2284667 21.6854002
Once 4.3857666 13.1572999
Totalling... 36.0000000
Setting the thrice to 3 cm^2 then has the total coverage rise....
Thrice 3 3.0
Twice 1.0237947 3.0713841
Once 14.952411 44.857233
Totalling... 50.9286171
Neither of these optimums fit the specifications given.
I'd conclude that the problem is geometrically impossible...
:-)
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