-> If that code doesn't work, then employee1 must not be a pointer.  Do
-> you have some code like this up there?
-> Employee *employee1;
-> employee1 = new Employee;
Hmmm i created the object automatically with something like
employee employee1;
So is it necessary to create the object manually with the pointer?
-> BTW: That is a nice raise :)
I'm generous what can I say. :)
Thank you,
Phil
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