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| subject: | DIGITAL CLOCKS |
MIKE ROSS wrote in a message to ROBERT SAYRE: MR> The problem is that the capacitance of a diode increases as its MR> reverse bias voltage becomes smaller. Why is diode capacitance a problem? MR> The diode capacitance actually becomes a maximum just as it starts MR> to conduct. Just before, actually. The junction still needs to be slightly reverse-biased. And the minimum reverse-bias gives the same effect as having those capacitor plates *real* close together. MR> The choice of Schottky diodes is because they have a low forward MR> voltage and can be made very tiny with very little capacitance. Tiny in terms of the area of the junction? Or something else? ---* Origin: TANSTAAFL BBS 717-838-8539 (1:270/615) SEEN-BY: 633/267 270 @PATH: 270/615 150/220 379/1 633/267 |
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