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| subject: | Re: change A to E |
BB> I now know what is happening but it is interesting the first time you see i BB> /* you forgot to include the header to compile it right. BB> mov si,offset dat BB> mov AH,0ah ;change AH to 0eh and run again BB> mov bx,0 BB> mov cx,11 i thought it was a trick but no, the string is just printed reverse side. --- Renegade v5-11 Exp ---------------* Origin: CoM BBS (merely seeking the truth) (1:167/146) |
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