->  DW> Okay. Here's today's version. I discovered that Q1 
->  DW> and Q2 must be integers. Formerly, I thought they 
->  DW> could also be half-integers, so that their sum and 
->  DW> difference (D and E) would be integral. However, 
 
-> just remember that in my definition of Pythagorean Triples, they are whole 
-> numbers... not decimal fractions... i've not tried any of your code because  
-> don't know if it'll run on what i have available... also, i'd like to see it 
-> write to a text file instead of just to the screen... its been too long sinc 
-> looked at BASIC... almost 30 years or so ;) 
 
-> )\/(ark 
  
Yup. But my numbers Q1 and Q2 are NOT the lengths of the sides 
themselves. They are numbers that are used to calculate the sides, so 
that: 
  
E = Q1 + Q2 
D = Q2 - Q1 
  
A = (E^2 - D^2)/2 
B = E*D 
C = (E^2 + D^2)/2 
  
A, B and C are the actual lengths. 
  
It's easy to prove that E and D must be integers. But, at least in 
simple theory, Q1 and Q2 could have half-integral values. For example, 
if Q1 = 1.5 and Q2 = 3.5, E would be 5, and D would be 2. 
  
But now I see why this can't be true. E and D must *both* be odd 
numbers. 
  
                           dow 
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