G'morning David,

 DW> Incidentally, the "S - 1 OR 1" expression finds the
greatest ODD number
 DW> that is less than or equal to S. I think that's about the easiest way
 DW> to do it.

Neat !

 DW> Here's the latest. Not many changes.

Unfortunately, my quick timer addition uses time$ which does not 
report parts of seconds;  this version still clocks in at 4 
seconds here...

:-))
 
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