AM> BW>   cout << "The value of /a is " << (char)'/a' << endl;
AM>   Shouldn't the above give an error? '/a' is more than one
AM>   char. I think you meant '\a' which is an escape code.
   He meant '/a', but you are correct.
   Most compilers in the 16-bit world will give you an error:
Too many integers in constant
   Or something like that. There must be exceptions in either
   platform or usage, however, since he has used this before.
   As you have probably found out, it doesn't work well in
   most circumstances, generating an error.
> ] OOPS! I guess they DO fall off the edge of the world........
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