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| subject: | Re: Organizing source code |
From: "Paul Ranson"
How many bytes of assembly language does it take to print two floating point numbers?
If you look at the assembly language output from your C++ compiler you'll
see that your entire program is devoted to printing two pre-calculated
constants.
Paul
"Geo" wrote in message news:417bbeea{at}w3.nls.net...
> "Ellen K."
wrote in message
> news:gpmmn0pocdcqnrk79vui9ogbesbusjtigd{at}4ax.com...
>
>> >when the heck would you use a float number instead of using double?
>
>> To save space.
>
> ROFL!!!! In a language where you use MFC?
>
> Speed I'll accept, if it can process float faster than double then great
> but
> saving space? I mean this
>
> #include
> int main()
> {
> double a, b;
> a=15/2;
> b=15.0/2;
> cout << a << " " << b << "\n";
> return 0;
> }
>
> compiles to a 193K executable, written in assembler that would probably be
> less than 40 bytes. How worried about space can a C++ programmer be?
>
> Geo.
>
>
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