From: "Paul Ranson" 

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One neat thing you could do,

#include 

int balls [ 50 ] ;
for ( int i =3D 0; i < 50; ++i )
   balls [ i ] =3D i + 1 ;
std::random_shuffle ( balls, balls + 50 ) ; std::sort ( balls, balls + 3 ) ;
m_pick4.Format ( "%d-%d-%d-%d", balls [ 0 ], balls[ 1 ], balls[ 2
], = balls[ 3 ]) ;

to output the chosen numbers in ascending order...

Paul
  "Paul Ranson"  wrote in message =
news:41b3660d{at}w3.nls.net...
  'rand' returns a pseudo random number between 0 and 32767. So in your =
application 8 and 9 should come up slightly less often than 0-7. To do a =
lotto type thing I think a shuffle is appropriate, luckily C++ contains =
the exact function you want....

  #include 

  int balls [ 50 ] ;
  for ( int i =3D 0; i < 50; ++i )
     balls [ i ] =3D i + 1 ;
  std::random_shuffle ( balls, balls + 50 ) ;
  m_pick4.Format ( "%d-%d-%d-%d", balls [ 0 ], balls [ 1 ], balls [ 2 ], =
balls [ 3 ]) ;

  etc.

  I'm pretty sure that that uses the 'rand' function internally, so your =
method for setting the generator would still apply. I'll take a look =
later. This approach also deals with the '0' issue since most lotteries =
choose from 1-n rather than 0-n-1... You can supply your own random =
generator to 'random_shuffle' but this is syntactically a bit trickier.

  I found http://www.paradisepoker.com/shuffling.html interesting, if =
you want to do this properly then there are quite a lot of things to = think about.

  Paul
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One neat thing you could do,
 

#include=20
<algorithm>
 
int balls [ 50 =
]=20
;
for ( int i =3D =
0; i < 50;=20
++i )
   =
balls [ i ] =3D i=20
+ 1 ;
std::random_shuffle ( balls,=20 balls + 50 )
;
std::sort ( balls, balls =
+ 3 )=20
;
m_pick4.Format =
(=20
"%d-%d-%d-%d", balls [ 0 ], balls[ 1 ], balls[ 2 ], balls[ 3 ]) =
;
 
to output the chosen numbers in ascending order...
 
Paul

  "Paul Ranson" <paul{at}barkto.com>">mailto:paul{at}barkto.com">paul{at}barkto.com>
wrote in =
message news:41b3660d{at}w3.nls.net...
  'rand' returns a pseudo random number between 0 =
and 32767.=20
  So in your application 8 and 9 should come up slightly less often than =
0-7. To=20
  do a lotto type thing I think a shuffle is appropriate, luckily =
C++=20
  contains the exact function you want....
   
  #include=20
  <algorithm>
   
  int balls [ =
50 ]=20
  ;
  for ( int i =
=3D 0; i < 50;=20
  ++i )
     =
balls [ i ] =3D=20
  i + 1 ;
  std::random_shuffle (=20
  balls, balls + 50 ) ;
  m_pick4.Format (=20
  "%d-%d-%d-%d", balls [ 0 ], balls [ 1 ], balls [ 2 ], balls [ 3 ])=20
  ;
   
  etc.
   
  I'm pretty sure that that uses the 'rand'
function =

  internally, so your method for setting the generator would still =
apply. I'll=20
  take a look later. This approach also deals with the '0' issue since =
most=20
  lotteries choose from 1-n rather than 0-n-1... You can supply your own =
random=20
  generator to 'random_shuffle' but this is syntactically a bit=20
  trickier.
   
  I found http://www.paradisep" target="new">http://www.paradisep=">http://www.paradisepoker.com/shuffling.html">http://www.paradisep=
oker.com/shuffling.html=20
  interesting, if you want to do this properly then there are quite a =
lot of=20
  things to think about.
   
  Paul

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