From: "Geo" 

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Oh nevermind, you are only sorting the balls I'm using not the whole = batch.

Geo.
  "Paul Ranson"  wrote in message =
news:41b366f5{at}w3.nls.net...
  One neat thing you could do,

  #include 

  int balls [ 50 ] ;
  for ( int i =3D 0; i < 50; ++i )
     balls [ i ] =3D i + 1 ;
  std::random_shuffle ( balls, balls + 50 ) ;
  std::sort ( balls, balls + 3 ) ;
  m_pick4.Format ( "%d-%d-%d-%d", balls [ 0 ], balls[ 1 ], balls[ 2 ], =
balls[ 3 ]) ;

  to output the chosen numbers in ascending order...

  Paul
    "Paul Ranson"  wrote in message =
news:41b3660d{at}w3.nls.net...
    'rand' returns a pseudo random number between 0 and 32767. So in =
your application 8 and 9 should come up slightly less often than 0-7. To =
do a lotto type thing I think a shuffle is appropriate, luckily C++ =
contains the exact function you want....

    #include 

    int balls [ 50 ] ;
    for ( int i =3D 0; i < 50; ++i )
       balls [ i ] =3D i + 1 ;
    std::random_shuffle ( balls, balls + 50 ) ;
    m_pick4.Format ( "%d-%d-%d-%d", balls [ 0 ], balls [ 1 ], balls [ 2 =
], balls [ 3 ]) ;

    etc.

    I'm pretty sure that that uses the 'rand' function internally, so =
your method for setting the generator would still apply. I'll take a = look
later. This approach also deals with the '0' issue since most = lotteries
choose from 1-n rather than 0-n-1... You can supply your own = random
generator to 'random_shuffle' but this is syntactically a bit = trickier.

    I found http://www.paradisepoker.com/shuffling.html interesting, if =
you want to do this properly then there are quite a lot of things to = think about.

    Paul
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Oh nevermind, you are only sorting the =
balls I'm=20
using not the whole batch.
 
Geo.

  "Paul Ranson" <paul{at}barkto.com>">mailto:paul{at}barkto.com">paul{at}barkto.com>
wrote in =
message news:41b366f5{at}w3.nls.net...
  One neat thing you could
do,
   
  
  #include=20
  <algorithm>
   
  int balls [ =
50 ]=20
  ;
  for ( int i =
=3D 0; i < 50;=20
  ++i )
     =
balls [ i ] =3D=20
  i + 1 ;
  std::random_shuffle (=20
  balls, balls + 50 ) ;
  std::sort ( balls, =
balls + 3=20
  ) ;
  m_pick4.Format (=20
  "%d-%d-%d-%d", balls [ 0 ], balls[ 1 ], balls[ 2 ], balls[ 3 ]) =
;
   
  to output the chosen numbers in ascending order...
   
  Paul
  
    "Paul Ranson" <paul{at}barkto.com>">mailto:paul{at}barkto.com">paul{at}barkto.com>
wrote in =
message news:41b3660d{at}w3.nls.net...
    'rand' returns a pseudo random number between 0 =
and 32767.=20
    So in your application 8 and 9 should come up slightly less often =
than 0-7.=20
    To do a lotto type thing I think a shuffle is =
appropriate, luckily C++=20
    contains the exact function you want....
     
    #include=20
    <algorithm>
     
    int balls [ =
50 ]=20
    ;
    for ( int i =
=3D 0; i <=20
    50; ++i )
       balls [ i ]=20
    =3D i + 1 ;
    std::random_shuffle (=20
    balls, balls + 50 ) ;
    m_pick4.Format (=20
    "%d-%d-%d-%d", balls [ 0 ], balls [ 1 ], balls [ 2 ], balls [ 3 ])=20
    ;
     
    etc.
     
    I'm pretty sure that that uses the 'rand' =
function=20
    internally, so your method for setting the generator would still =
apply. I'll=20
    take a look later. This approach also deals with the '0' issue since =
most=20
    lotteries choose from 1-n rather than 0-n-1... You can supply your =
own=20
    random generator to 'random_shuffle' but this is syntactically a bit =

    trickier.
     
    I found http://www.paradisep" target="new">http://www.paradisep=">http://www.paradisepoker.com/shuffling.html">http://www.paradisep=
oker.com/shuffling.html=20
    interesting, if you want to do this properly then there are quite a =
lot of=20
    things to think about.
     
    Paul

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