*** Darryl Gregorash wrote in a message to All:
DG> Thinking back to the good old days, when 640K and a 10 meg
DG> MFM hard drive was considered "enough".. or even earlier, to
DG> the days before DOS 1.1 (for the young-uns here, DOS 1.1 was
DG> when the first "fixed" disk support arrived):
DG> A software developer's definition of "enough mass storage
DG> volume": if you can afford it, it isn't enough.
DG> (I wonder how many 360K floppies it would take to distribute
DG> OS/2 or WinNT? :)
Win 95B takes up something like 28 or more diskettes, all of them in DMF
format (well, I've only seen it on CD-ROM, but the CAB files are in
diskette-sized chunks). 1.7M x 28 / 360K = ?
Grr.. what happened to my calculator? Oh well... 360Kx2 = 720K, x4=1440K, x5
= 1800K, which is approximately correct. Let's figure 28 MDF diskettes for
the CAB files and two more for the executable, to give a round number of 30.
So, 30x5 = ... well, that kinda math is too complex for me, I'll let you
figure it out. ;)
--Scott.
--- timEd 1.01
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* Origin: Wizard's, 254-554-2146, Abacus PLUS, 903-3097 (1:395/11)
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