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| subject: | 32-bit bink hack |
Paul Edwards wrote in a message to Phil Crown:
PC> What's the bug in EMX? I might run across it and not even notice it,
PC> thinking its in *my* code. :-)
PE> /* According to my interpretation of ISO/IEC 9899:1990, this
PE> program should print "2". It prints "-1"
instead, under
PE> EMX 0.9a. */
PE> #include
PE> int main(void)
PE> {
PE> char buf[50] = "5 6";
PE> int x, y;
PE> int ret;
PE>
PE> ret = sscanf(buf, "%d %d p", &x, &y);
PE> printf("ret is %d\n", ret);
PE> return (0);
PE> }
I think that EMX is behaving correctly. If 'p' is not matched exactly,
that is a failure of the input stream, and sscanf() should return EOF.
I checked using Borland C and Watcom C, and both return 2. Reading the
spec document, however, suggests that the proper return is, in fact, EOF.
-- Mike
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