-> Pretty sure there isn't a type, but I'll have to double check. YOu see, it 
-> wasn't typed in, cut and pasted from my source code... 
 
-> Pretty sure the results are accurate, but might have grabbed from wrong 
-> source. Sometimes I forget to make revisions through trial runs. 
  
I am 99.999999% sure that there *is* a typo in the "metric" formula you 
posted. The little program I posted here a couple of nights ago, that 
uses both the metric and the English formula to perform the same 
calculation (after conversions of the units of the input quantities), 
produces essentially identical results, within a few hundredths of a 
degree, but *only* if that final "+" in the metric formula is changed 
to a "*". Without this change, the two formulae give substantially 
different results. I also tried putting a "+" in the English formula, 
but this, too, produced results that didn't agree. 
  
If you didn't make the typo, then it must have been made by someone 
previously. I wonder if people have been using the erroneous version, 
and maybe not realizing that the results were wrong. 
  
                          dow 
  
---------------------------------------------------- 
  
INPUT "Temp (deg. C.)"; T 
INPUT "Windspeed (metres per second)"; V 
  
W = 13.13 + .62 * T - 13.95 * V ^ .16 + .486 * T * V ^ .16 
IF W > T THEN W = T 
PRINT
">>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>>";

PRINT TAB(50); "Windchill: "; W; "deg. C." 
  
PRINT "Fahrenheit temp: "; 
T = 1.8 * T + 32 
PRINT T; "deg. F." 
  
PRINT "Windspeed in miles per hour:"; 
V = V * 2.237 
PRINT V; "mph" 
  
W = 35.74 + .6215 * T - 35.75 * V ^ .16 + .4275 * T * V ^ .16 
IF W > T THEN W = T 
PRINT "Windchill: "; W; "deg. F., 
>>>>>>>>>>>>>>"; 
  
W = (W - 32) / 1.8 
PRINT TAB(50); "which is:  "; W; "deg. C." 
PRINT 
END 
  
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