BG>>         *f=1/*f;
 JdB> His algorithm still produces the correct result here (since you
 JdB> haven't used any character or string literals).
 BG> True, depends on if my function above, includes a 
 BG> comment or not. My compiler (most others as well) 
 BG> reckons it does.
 BG> What does the spec say about this?
The spec says the above includes a comment.
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