* Reply to message in Sysop's Personal Mail

Hello Francois!

Replying to a message of Francois Thunus to Steven Cox:


 FT> nope. Return is just what the procedurue should return to the call so
 FT> what happens is that when you run the program factorial is called
 FT> with 5 as an argument.   It calls factorial with 4 as an argument;    
 FT> That  calls factorial with 3 as an argument       that calls
 FT> factorial with 2 then         factorial with 1 then           
 FT> factorial with 0 bingo ! the procedure has the answer: that's 1           
 FT> the answer is sent back (returned) to the previous level: answer is
 FT> factorial(1) can now be processed; It is 1*1 the answer is returned
 FT> to previous level which can be processed:       factorial(2) is 2*1
 FT> answer is returned to previous level     factorial (3) is treated:
 FT> it's 3*2, answer is returned to previous level   factorial(4) is
 FT> processed: it's 4*6, answer is returned to previous level factorial 5
 FT> is processed: it's 5*24, ie 120.

 FT> the problem is solved.

Now I understand!!  I will go back & finish that lesson now.


Thanks so much for your help,
 

Steven

--- FleetStreet 1.03 NR==LoraBBS OS/2 v2.40+