John Beal wrote in a message to Richard Skinner:

RS> I was wondering, in pascal, how do I return the Cube Root of
RS> a number?

 JB> If you have log and antilog functions available, then the
 JB> nth root of x would be:

 JB>   e ^ ((ln x)/n)

 JB>   or 

 JB>   10 ^ ((log x)/n)

ARRGH!
                            (1/n)
       ((ln x)/n)     (ln x)         (1/n)
      e            = e            = x

 JB> Get the log (natural or base 10) of the base, divide by the
 JB> power, and get the antilog of the result, this is the nth
 JB> root of the base.

Does anyone remember fifth grade?!
 
-- Mike


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