hi Mike,

 * Re:
   to   John Beal
   sub. Cube Root
 MB> ARRGH!

 JB>> Get the log (natural or base 10) of the base, divide by the
 JB>> power, and get the antilog of the result, this is the nth
 JB>> root of the base.

 MB> Does anyone remember fifth grade?!

Yes, but what we remember from it, isn't
 MB>                             (1/n)
 MB>        ((ln x)/n)     (ln x)         (1/n)
 MB>       e            = e            = x
but the sex stuff:-)

regards,
         hugo