>         printf("Unsigned Ints have %u bits.\n",
 >                sizeof(unsigned int) * CHAR_BIT);
 
JdBP>   Strictly speaking, it's not portable.  Although it is generally agreed
JdBP>   that in ISO Standard C there are no "hidden bits" in
an unsigned char
JdBP>   (in order to satisfy some of the semantics of memcpy()), it is *not*
JdBP>   guaranteed that other integral types will not have hidden bits.

That's the first time I've heard that.  Can you quote something
that says that?  BFN.  Paul.
@EOT:

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