Hi coder,
 CC> The following pseudo-code has an unfortunate side effect:
 CC> (using Borland c++ 4.51)
 CC> ofstream outf("out.bin");
 CC> char string[6];
 CC> strcpy(string,"12345");
 CC> string[strlen(string)] = '\n';
 CC> outf.write(string, strlen(string));
 CC> outf.close();
 CC> The side effect is that it writes the following:
 CC> 12345#13#10           (where #13 & #10 are ascii characters)
 CC> What the hell am I doing wrong?
 "12345" won't mean that U will have |1|2|3|4|5| in memory, but that U will
 have |1|2|3|4|5|#0| ( when #0 means end of string )
 Then, if U make only a printf with string after put a |#13|#10|, 
 he will write :
 
 12345
 dfhdfh#^!‡{djghjŠ(^^^!‡Š{^#@@!(‡'—æ$
 ... and so on ... until he found a #0
 --Hoping it would be useful 2 U--
 Ciao
                                FeP
... Coding is so funny...
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