BP>  CR> If you are overloading the global new operator, you won't be ab
BP>  CR> get the 'original' global new.
BP> Why? Overloading never removes an existing function. You can define
BP> new() functions that take different number and/or type of arguments,
BP> will still have the original new.
Both of you are right.
Cliff  meant "If you provide your own implementation of the global new
operator...". In that case,  the  'default'  implementation  can't  be
accessed.
If you overload it, the case is different of course.
Thomas
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 þ MM 1.0 #0113 þ Everyone hates me because I'm paranoid.
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