-=> On 03 Jun 96  19:22:45 Mike Bilow said to Vitus Jensen <=-

 MB> You can figure them out yourself or
 MB> study the IBM source examples, but is not explicitly stated that the
 MB> tail end of memory space after an IORB is valuable for use as a status
 MB> block or other structure. MS C 6.0 also achieves powerful
 MB> optimizations if the IORBs are allocated on a power-of-two boundary,
 MB> such as 128 or 256 bytes, with the slack space used as described. 
 MB> These are really tricks to take advantage of the compiler, but most
 MB> device driver programmers do not know them. 

Coming from DOS, I was thinking that the IORB is memory in the caller's
address space. I realse that OS/2 must actually make a copy, but how
can yiou be sre that the IORB is bigger than the particular IOReqst
requires? And how much bigger? And for how many future upgrades?

If its a popular sport to do this, then presumably IBM will have
to support it in future releases. If so, documentation will be required.
Please can we know?

ANdrew

 
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