Hello Mike!

Friday August 09 1996 19:16, Mike Burgett wrote to All:

MB> struct TestRegEx *temp;
MB> count = 0;
MB> while(temp = testmask[count++])
MB> {
MB>   if (regexec(&(testmask[count]->expr), checkstring, 0, 0) == 0);
MB>     break
MB> }

I'm hoping you typed this in by hand . Unless I'm missing
something in your code, you're always skipping the first regex_t. You're
also missing the last parameter of the regexec() call.

MB> if I feed it two mask strings, zee* and ab* (in that order) and send
MB> test01.dat, zee000.dat, and test02.dat through the regexec() call, I get a
MB> match on the second mask for the first string, and a match on the first
MB> mask for the second string, and then a match on the second mask for the
MB> third string.

MB> playing with the mask string, it seems that it doesn't matter what I set it
MB> to, j* matches test01.dat and test02.dat as well.....

Ok, you really need to read up on regular expressions . The '*'
modifier means to match 0 or more of the preceeding character. Hence,
'zee*' will match 'ze' and 'zeeeeee'. 'ab*' is matching the 'a' in 'dat'.
'j*' will match anything.

You probably want 'zee.*' and 'ab.*'. Here is a sample util I just whipped up.


-- CUT -------- Begin test.cpp -------- CUT --
#include 
#include 

const char *searchStrings[] = {"zee.*", "ab.*"};
const char *testData[] = {"test01.dat", "zee000.dat",
"test02.dat"};

int main() {
   regex_t regularExpressions[2];
   int i = 0;
   int j = 0;

   for (i=0; i<2; i++) {
      regcomp(®ularExpressions[i], searchStrings[i], REG_EXTENDED |
REG_ICASE | REG_NOSUB);
   }

   for (j=0; j<3; j++) {
      for (i=0; i<2; i++) {
         if (regexec(®ularExpressions[i], testData[j], 0, 0, 0) == 0) {
            cout << searchStrings[i] << " matches "
<< testData[j] << endl;
         }
      }
   }

   for (i=0; i<2; i++) {
      regfree(®ularExpressions[i]);
   }

   return 0;
}
-- CUT --------- End test.cpp --------- CUT --

Doug

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