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| subject: | Computer dead end |
Hello Bob. 30 Jun 04 12:32, you wrote to Rod Gasson: BL> You have to terminate it at *one* end, or the system will be running BL> into an open-circuit generating 20V! But that's got nothing to do with BL> the cable. if you used a standard terminator on one end wouldn't you get only half the expected impedance, how many volts would you get then? 13.3 ? and what's it supposed to be? 10v ? BL> The delay along a 10-metre 50-ohm cable would be something like 5 BL> nanoseconds, but so what, when there are only two computers, one at BL> each end? The delay is goign to exist anyway, and when it reaches BL> the 50-ohm termination at either end it will be absorbed anyway. but before it is absorbed it bounces back and reinforces the signal seen on the cable. BL> A BL> short cable will have negligible delay. BL> The other thing I mentioned was the length. A long lossy cable (thin BL> cable) ends up looking like 50-ohms anyway. There are reflections, but BL> they are lost on the way back. For that thin cable, 10-metres will BL> be as good as infinity. at 10Mhz I don't think there'd be be much loss over 10m RG>> It took me much experimenting before I discovered I needed the RG>> "T" at BOTH ends, and that both ends needed to be terminated RG>> before it would work. BL> Rubbish. On a one-metre cable, it wouldn't matter a rat's arse BL> *where* you terminated it, all the way up to a gigahertz. yeah, but I get the feeling that the ethernet cards refuse to work unless they see a 25 ohm load. as you say I seen no reason why it wouldn't work with a single terminator but I feel it'd need to be a 25 ohm resistor. 22 ohms would probably be close enough... Hmm I'll have to score some T connectors and liberate one of my BNC cables from the video lash-up and try it myself. --- GoldED+/LNX 1.1.4.7* Origin: (3:640/1042) SEEN-BY: 633/104 260 262 267 270 285 640/296 305 384 531 954 1042 690/734 SEEN-BY: 712/610 848 774/605 800/221 445 @PATH: 640/1042 531 954 633/260 267 |
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