Can someone give me a definitive answer as to how OS/2 handles
scheduling in the following scenario:


A low priority process (A) is scheduled and running
A higher priority process (B) is blocked (probably on a com port)

The process B becomes ready to run (by way of receiving a char)

Question:
Does process A get pre-empted immediately or does the scheduler wait
until the slice allocated to process B has finished?

My own experiments tend to indicate that OS/2 does *not* immediately
pre-empt any low priority process when another higher priority process
becomes ready to run.

If this is the case then it's a major *pain* and results in a
significant amount of wasted CPU time when running high-priority
processes that are frequently blocked for just over one timeslice (which
is not uncommon in some areas of development)

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