KY> void test( int i )
 KY> {
 KY> i=5;
 KY> return;
 KY> }
 KY> You're not getting a pointer back,
 
 CD> You aren't getting anything back!!
 KY> Sure you are!   You're getting the modified value of i.  In the
 KY> above, i would be an "in/out" parameter.
 
 Yes, you've modified 'i' in the routine, but there's no way that the
 calling routine can access the changed value of 'i'.  If you change
 the definition of test to:
 void test (int& i) {...}
 Then you could get back some sort of answer.
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 þ Blue Wave/QWK v2.12 þ
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