So sayeth the Book of Downs, "Conversion of pointer."
 This was taken out of context.  It made a lot more sense in the 
 original post, however...
 
 KY> void test( int i )
 KY> {
 KY> i=5;
 KY> return;
 KY> }
 KY> You're not getting a pointer back,
 CD> You aren't getting anything back!!
 Sure you are!   You're getting the modified value of i.  In the above,
 i would be an "in/out" parameter.
 CD> How about this one...
 CD> int test()
 CD> {
 CD> return 5;
 CD> }
 CD> Kinda questionable in the utility department....
 I was just using the code the original poster used.  In his example, he
 was setting the variable to 5, so that's all I was doing.
 
 -=Kevin=-
                                            
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