>>> Bob Sewell on Infinity
BS> This also shows that Z+ = w and Z = w and that w (the infinite
BS> set of positive integers) equals what looks like 2 * w (all the
BS> integers, positive and negative).
The bijection that proves that Z+ = Z, is x x+1 over non-negative x.
What's w, an arbitrary infinite number? Which one?
BS> I can also show that the set of all even integers 2Z is countably
BS> infinite, which by the definition of cardinality, means that this
BS> infinite set has the same cardinality as Z+, and by the last proof,
BS> the same cardinality as Z. This is one way of saying that, as far as
BS> cardinality goes, Z = Z+ = 2Z.
Elementary.
BS> If you want, I'll show that the cardinalities of the set of
BS> positive rational numbers equals that of the set of *all* rational
BS> numbers equals that of Z+. I can show that the set of all real
BS> numbers between 0 and 1 is uncountable, and yet this set has the same
BS> cardinality as the set of *all* real numbers, which is a way of
BS> stating that w ^ w = w.
Set D = the denumberable cardinality of the integers, C = the cardinality of
the continuum. So the cardinality of the interval (0,1) = C. Now the real
numbers can be broken into a denumberable number of intervals (n,n+1) for all
integers positive and negative. Hence the cardinality of the the real number
line is D * C = C. It is not C^C, that is something else.
A plane has one horizontal line thru each point of a vertical axis. Hence
the cardinality of the plane is C * C = C. Continuing, the cardinality of
space is C^3 = C and of n dimensional space C^n = C.
BS> I'm not following where this is leading or how it relates to
BS> whether or not w ^ w > w or not.
You agree that A^A > 2^A? I maintain that 2^A > A. Hence A^A > A and cannot
equal A. By decimal or binary notation for real numbers 10^D = 2^D = C and
C > D as you say you can prove. Indeed you can by a Cantor diagonal
argument. Hence as I maintain, 2^D > D.
What is a proof for A + B = max(A,B) when either A or B is infinite?
Actually A + A = A for infinite A would suffice.
Card(S) + Card(T) = max(Card(S), Card(T)) for arbitrary infinite sets S & T.
Proofs for integers and reals are easy, but for any sets, what's the proof?
Actually Card(S) + Card(S) = Card(S) for infinite set S would suffice.
---
---------------
* Origin: Sunken R'lyeh - Aloha, OR (503) 642-3548 (1:105/337)
|