In response to a message to All on ...
RC>The professor challenged me to find one for 7.
Sorry this is so late - there *is* a rule, but it has been so long
since I've used it that I'm not sure if I remember it correctly.
Here's ow I *think* it goes...
Start with a number, cross off the last digit, subtract twice that
deleted last digit from the remaining portion of the number. Repeat
the process. as needed. if the remainder is 0 or any other
multiple of 7, the number is divisible by 7.
Example...
2156 Start with this number, cross off the six, leaving...
215 but now subtract 2 x 6 (12)...
-12
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203 Repeat the process - drop the 3...
20 and double the 3 (6) to subtract...
-6
__
14 remainder is 14, a multiple of 7, so 2156 is divisible by 7.
Sorry I'm so far behind in the mail or I might have gotten this to
you on time.
Chuck Beams
cbeams@dreamscape.com
http://www.dreamscape.com/cbeams
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