Hi Chris.

23-Feb-04 04:31:09, Chris Hoppman wrote to All


 CH> Was wondering what this is about.

 CH> b:boolean; by:byte; ---

 CH> b := (by and 6 = 6);

 CH> ---

 CH> I have it in two places in my com routines that I am tring to
 CH> convert to asm and don't really know how it goes about evaluating
 CH> this experssion.  So, don't know if I can convert it.

something like

   mov al,by
   and al,6
   cmp al,6
   jnz {at}ZZ0
   mov b,1
   jmp {at}ZZ1
 {at}ZZ0:
   mov b,0
 {at}ZZ1:


 CH> I saw in the help file.  If by = 6 then it's true/ if by  6 then
 CH> it is false and via versa, but what does = 6 at the end of it
 CH> play.

 CH> I understand this.  b := (by and 6), but don't understand b:=(by
 CH> and 6 = 6);

do you understand this?  b:= (by = 6)

  b:=(by and 6 = 6);  means the same as   b:=((by and 6) = 6);

does that help ?

 -=> Bye <=-

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