John Edser wrote:
>>BOH:-
>>But then if sets A and b are your sets of fitness elements, the 
>>statement "All the elements in the intersection C are also in
sets A and 
>>B" is false.
> 
> 
>>JE:-
>>We are travelling in endless circles. 
>>I have proven that in this case
>>"All the elements in the intersection 
>>C are also in sets A and  B". Thus
>>I ask you to provide proof that that
>>in this case, they are not.
> 
> 
> BOH:-
> I was replying to this:
> "...I am proposition that each fitness element was produced asexually by 
> just one parent so that each Venn circle represents a _total_ fitness 
> for _one_ parent".
> 
> Which seems to say that each element only has one parent, and each set 
> is the set of fitness elements produced by a parent.  If each element 
> only has one parent, it can only be a member of one set.  Hence, it 
> cannot be in two sets, so it cannot be in an intersection.
> 
> JE:-
> Incorrect inference.
> "If each element only has one parent, it 
> can only be a member of one set.  Hence, it 
> cannot be in two sets, so it cannot be in 
> an intersection", is NOT a correct inference.
> 
> It is true that: "If each element only has one parent, 
> it can only be a member of one set" where that set
> represents the absolute fitness set of that parent
> AND no sets are intersected.
>  
So, if no sets are intersected, then there are no intersections.

> If and only if, each set element within every
> absolute fitness set, i.e. each fitness element, 
> is _eqivalent_within one population THEN
> each absolute fitness set CAN be intersected. 

Right, they can be intersected, but they only will be intersected if 
there is an element that is a member of both sets.  i.e. if it has two 
parents.

When
> they are 100% intersected all the logical orders
> of selection are produced _exactly_, without 
> cognition.
> 
> _____________________________________________________
> Nothing forbids each absolute (total) set of parental 
> fitness being 100% intersected within one population,
> by either biology or mathematics, when each fitness 
> element was produced asexually and not sexually from
> each parent, as long as each fitness element is 
> defined as equivalent. It is that simple!

Except that you've already used the biology to define the system in such 
a way that there is no mathematical intersection.

Bob

-- 
Bob O'Hara

Rolf Nevanlinna Institute
P.O. Box 4 (Yliopistonkatu 5)
FIN-00014 University of Helsinki
Finland
Telephone: +358-9-191 23743
Mobile: +358 50 599 0540
Fax:  +358-9-191 22 779
WWW:  http://www.RNI.Helsinki.FI/~boh/
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