Hi Bo! :-)

 BS> On little endian machines it should just be defined as fido_swap(x)
 BS> with no action?
Yes, right.

 PS>> Or do something like this:

 PS>> void swap16(uint16_t *orig)
 PS>> {
 PS>>     uint8_t x,y;

 PS>>     x = *(uint8_t *) orig;
 PS>>     y = *(((uint8_t *) orig)+1);

 PS>>     *orig = x + y * 256;
 PS>> }

 PS>> That should work on both big and little endian machines, if *orig is
 PS>> read from disk and is stored there in little endian byteorder.

 BS> Aha smart!
Best try it on a big endian machine first, though, I didn't actually try to
compile or run this piece of code. I don't even know if it works on a
little endian machine. It should, but I may have made mistakes.

Ciao
Pascal

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