> if speed is a issue, don't multiply either :)

 >  #include 
 >  #include 
 >  #include 
 >  int main(void)
 >  {   int n,s;
 >      const int top=(int)sqrt(INT_MAX)*2;
 >      for(n = -1,s=1; n < top; n+=2) printf("%d %d %d
 > \n",s+=n,n*n, top);
 >      return 0;
 >  }

    Don't understand, Jasen. You yourself are multiplying.

Best Wishes,
Bill.

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