Hi Jay.

24-Apr-04 10:46:12, Jay B wrote to All


 JB> From: "Jay B" 

 JB> Hey, I got the following code:

 JB> int main(void) {
 JB>     return 0;
 JB>     int i = -33;

 JB>     printf("%d\n", i);
 JB>     printf("%d\n", (unsigned int)i);
 JB> }

 JB> I get -33 for both, why? Since I'm typecasting the second as an unsigned
 JB> int,
 JB> shouldn't it get rid of the negative sign

no, printf doesn't understand the type of the parameters you give it.
you have to tell it.

try this

     int i = -33;
     printf("%u\n", (unsigned) i);

here the signed value is printed asif it was unsigned.

     printf("%u\n", i);

here you'll probably get the same result.

It'll be some large positive number dependant upon the negative input
number and the design of the processor.

 -=> Bye <=-
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