From: Darin McBride 

On April 23, 2004 8:46 pm, Jay B wrote:
> Hey, I got the following code:
>
> int main(void) {
>     int i = -33;
>
>     printf("%d\n", i);
>     printf("%d\n", (unsigned int)i);
>     return 0;
> }
>
> I get -33 for both, why? Since I'm typecasting the second as an unsigned
> int, shouldn't it get rid of the negative sign?

But then you're "typecasting" it back to signed (%d).  Use %u for
unsigned integer output.

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