Hi Jerry,
   Moved this from the C echo.
::>  HB> I wonder if all those parenthesis are necessary?  How would the
::>  HB> compiler parse "x++++++++++++++"? 
::> It would tokenize it as:
::> x++ ++ ++ ++ ++ ...
::> However, as soon as the parser encountered the second ++, it'd give you
::> an error something like "Lvalue required" - `x' is an Lvalue, meaning
::> the ++ can modify it.  However, the result of `x++' is NOT an lvalue,
::> meaning the next `++' can't modify it, leading to an error.
Ok, I just bypassed the problem using a class. Here's the sample code I 
mentioned in the C echo:
===========test1.cpp===============
#include 
class test
{
  private:
    int x;
  
  public:
    test(){x=0;}
    test& operator++(int){x++; return *this;};
    friend ostream& operator<<(ostream& os, test& t);
};
ostream& operator<<(ostream& os, test& t){os << t.x; return os;};
int main(int, char *[])
{
  test tst;
  cout << "x = " << tst << endl;
  tst++;
  cout << "x = " << tst << endl;
  (tst++)++;
  cout << "x = " << tst << endl;
  tst++++;
  cout << "x = " << tst << endl;
  return 0;
}
==========end test1.cpp=============
It compiled and worked correctly. The output was:
x = 0
x = 1
x = 3
x = 5
So it CAN be done, just not in C or C/C++ with the built-in types.
#  Herbert Bushong    harchon@centuryinter.net       [TEAM OS/2]    
-  Blackbeard's BBS   Intelec: 239:600/0            
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---
   RM 1.31 2508   SYSOP: The guy laughing at your typing.
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