On (30 Oct 96) James Di Paulo wrote to All...
 JD> How does one calculate or measure the phantom power consumed
 JD> by things like TV's, VSR's, Steros and telephone answering
 JD> equipment when on standby or idle? What about computers, say a
 JD> 100 mg with all the attachmants (assume sound blaster,
 JD> printers, etc turned off)?
James, Get the current issue of Home Power! There's an article on
this very subject, with instructions for building a phantom load
measuring device. (One note - the exact resistor size is not
important, according to the author in an email message to me.)
 JD> Another...  If one buys a 10KW wind generator, assume the
 JD> impossible, 100% efficiency, is this equivalent to 300KWH per
 JD> month? (10K X 30 days.) If not, what is the monthly output?
10kW is the _maximum_ output. That means if the wind speed is at the
max rated value, it will put out 10 kW (watts are an instantaneous
measurement of the RATE of power use). If it ran at the speed for an
hour it would put out 10 kWh. If it ran at that speed for 30 _hours_
it would put out 300 kWh. 
The "monthly output" depends entirely upon your wind speeds. Get
some average wind speed data, look at the machine's power curves and
you could make a seat-of-the-pants guess at the monthly output.
                        Ian
... "There is more to life than increasing your speed."  - Ghandi             
 
... If government rests on the consent of the governed, when I stop 
onsenting
will they stop governing?
--- PPoint 1.96
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