JDP>How does one calculate or measure the phantom power consumed by things 
like
JDP>TV's, VSR's, Steros and telephone answering equipment when on standby or
JDP>idle? What about computers, say a 100 mg with all the attachmants (assume
JDP>sound blaster, printers, etc turned off)?
  It isn't phantom - it's real power consumed by those devices.  You pay
for it every month when you get your electric bill.  Wattmeters are
available which you can connect between the wall outlet and the device
under test to give you a reading of the power consumed.
JDP>Another...  If one buys a 10KW wind generator, assume the impossible, 
00%
JDP>efficiency, is this equivalent to 300KWH per month? (10K X 30 days.) If
JDP>not, what is the monthly output?
   The 10 KW is constant output, so if the machine runs for one hour,
you have generated 10 Kilowatt Hours of power.  Therefore:
   10KW output X 24 hrs/day = 240 KWH per day
   240 KWH X 30 days = 7200 KWH per month
   7200 KWH X $0.08 (my cost) = $576.00 per month value
   Of course, that is not realistic, as you mentioned, because you won't
get 100% output 100% of the time, unless you happen to have a hurricane
passing close by.
   Most homes don't use anything like that amount of power - something
like 1/4 to 1/2 that amount is more common.  The biggest power user if
the air conditioning system, but don;t underestimate the smaller loads
either.   As an example, my BBS computer network draws about 400 watts
(0.4 KW) all the time.  That breaks out to:
  0.4KW X 24 Hrs/day = 9.6KWH/day
  9.6KWH X 365 days/yr = 3504 KWH/year
  3504 KWH X $0.08 = $280.32 / year operating cost
  Ralph
---
 þ QMPro 1.53 þ ...and now Lorena for the Popeal Pocket Friend.
--- WILDMAIL!/WC v4.12 
---------------