NH> If I receive the four bytes in the order:  A B C D
NH> Is the proper way to rearrange these bytes:  B A D C
 
AL> According to my sources, no.
AL> A dword is not two words, it's byteswapped in full.

The way I learned was that converting from a big-endian 32-bit value
to a 32-bit little-endian value is really a two step process.

1)  The bytes in each 2-byte pair are swapped.  (BADC)
2)  The 2-byte pairs themselves are swapped.  (DCBA)

I think that the only difference between these two approaches is in
the semantics.

 * KWQ/2 1.2i *

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