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| subject: | Re: ATM Perfect zonal reading reference number generation |
From: Jerry Hudson
To: atm{at}shore.net
Reply-To: Jerry Hudson
The formula for the longitudinal aberration for any zone for a mirror under
test at the center of curvature is
L.A. = e^2 z,
where
L.A. = Longitudinal aberration: the distance
behind the central zone where a normal to the surface would intersect the
axis, in this case,
e = Eccentricity of the conic section:
Sphere => e = 0
Prolate ellipse => 0 < e < 1
Parabola => e = 1
Hyperbola => e > 1.
z = Sagitta for the mirror. For any conic, this
is
z = c r^2 / 2 - c^3 K r^2 / 8 + ...
where
c = Central zone's curvature = 1/R
r = Radius of zone from center of mirror
K = Conic constant = e^2 - 1, e the eccentricity
Note the reading for fixed source and moving knife edge will measure TWICE
the L.A. given above.
Note that this result is in contradiction to Texereau's, which I believe to
be in error. Accordingly, I enclose a derivation of my own formula.
- Jerry Hudson
Appendix: Derivation of L.A. for conic section under test
From Herzberger's formula for a conic section:
c K z^2 + 2 z - c r^2 = 0
where
c = Curvature = 1/R, R the vertex radius of curvature
K = Conic constant = e^2 - 1
z = Sagitta
r = Zone radius
Note that this can represent any conic section that is a surface of
revolution about the axis, with the vertex at r=0, z=0.
Differentiate the above with respect to r:
dz/dr = c r / (R + cKz)
Note that this is also the slope of the surface normal at r, which is equal to
slope = r / ( R - z + L.A. ).
It helps to draw a diagram, which I can't submit to the List,
unfortunately. Here's an attempt:
(Point r,z)
*- Surface normal:
/ \- Slope = r / (R - z + L.A.)
| | \-
/ \-
| | \-
-A--B------C--D
where the points
A = Vertex of curve
B = Point directly under the zone
C = Vertex center of curvature
D = Normal (ray) intercept
Note that AB = sag = z
AC = radius of curvature, R
CD = L.A.
B* = r
slope = B* / BD
Equating the two slopes, we obtain
r / (R - z + L.A.) = c r / (R + cKz),
L.A. = -R + z + (1 + cKz)/c
= (1 + K) z = e^2 z (Q.E.D.)
--- BBBS/NT v4.00 MP
* Origin: Email Gate (1:379/1.100)SEEN-BY: 633/267 270 @PATH: 379/1 633/267 |
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